# Friday Random Ten: from Prog to Neoclassical, with some Blues.

I haven’t posted one of these in a while, but I’m currently stuck waiting between very long and slow compiles, so I figured why not?

1. Echolyn, “Make Me Sway”: Brilliant track by Echolyn, one of the very best american neo-prog bands. One of the things that’s so distinctive about Echolyn is the way
that they use complex vocal harmonies better than anyone else.
2. Umphrey’s McGee, “Miami Virtue”: Ick. What a disappointment. I’d heard great things about Umphrey’s, and got their Mantis album, which was pretty good. So I got their latest album, “Death by Stereo”, which is absolutely atrocious. Ugh.
3. Tinyfish, “I’m Not Crashing”: Now this was a great discovery. I know nothing about them, but someone pointed them out to be on Twitter, and when I grabbed one of their albums, it knocked my socks off. This is seriously terrific neo-prog.
4. ProjeKct X, “The Business of Pleasure”: Weird. Very, very weird. This is one of Robert Fripp’s experimental instrumental gatherings of musicians. It’s strange stuff, but if you (like me) like interesting oddness, this is one of the most amazingly bizzare and yet great pieces of work you’ll find. Is it rock, jazz, or something else? Yes.
5. Cynic, “Nunc Sans”: progressive death metal with strong jazz influences? Yup.
6. Owl, “Sky Rocket”: Meh.
7. Gong, “Sold to the Highest Buddha”: How did I go for so long without learning about Gong? This is one of the very best of the Manchester prog bands. Amazing stuff, which never takes itself too seriously.
8. Jason Ricci and New Blood, “I Turned Into a Martian”: I don’t normally like blues much, but… Jason Ricci completely redefines what you can do with a harmonica. Despite not being a fan of the format, his playing is amazing, and he put together a great band to back him.
9. NOW Ensemble, “Change”: This is a big change of pace from the rest of this list. Here in NYC, there’s a really great organization called New Amsterdam Records. NAR is a non-profit label dedicated to promoting the NYC post-classical scene. The NOW Ensemble is my favorite of their stable of artists. Beautiful music by up-and-coming composers, brilliantly performed. I’ve embedded a Youtube link to a couple of their pieces below.
10. Steve Reich Ensemble, “Clapping”: This is a perfect demonstration of the beauty of simplicity. This piece consists of two people clapping the same pattern – but one periodically shifts by a beat, so that the pattern overlaps with itself in different ways. Embedded below is a ten-person variation on it.

# Categorical Equalizers

Category theory is really all about building math using composition. Everything we do, we do it by defining things completely in terms of composition. We’ve seen a lot of that. For example, we defined subclasses (and other sub-things) in terms of composition. It sounds strange, but it took me an amazingly long time to really grasp that. (I learned category theory from some not-very-good textbooks, which were so concerned with the formalisms that they never bothered to explain why any of it mattered, or to build any intuition.)

One thing that’s really important that we haven’t talked about yet is equality. In category theory, we define equality on arrows using something called a pullback. We’ll use that notion of equality for a lot of other things – like natural transformations. But before we can do pullbacks, we need to look at a weaker notion of arrow equality – something called the equalizer of a pair of arrows.

As part of my attempt to be better than those books that I complained about, we’ll start with intuition, by looking at what an equalizer is in terms of sets. Suppose we have two functions $f, g : A rightarrow B$.

Now, in addition, suppose that they have a not-empty intersection: that is, that there’s some set of values $x in A$ for which $f(x) == g(x)$. We can take that set of values, and call it $C$. $C$ is the equalizer of the functions $f$ and $g$. It’s the largest set $C$ where if you restrict the inputs to the functions
to members of $C$, then $f$ and $g$ are equal.

Now, let’s look at the category theoretic version of that. We have objects $A$ and $B$. We have two arrows $f, g : A rightarrow B$. This is the category analogue of the setup of sets and functions from above.

To get to the equalizer, we need to add an object C which is a subobject of A (which corresponds to the subset of A on which f and g agree in the set model).

The equalizer of $A$ and $B$ is the pair of the object $C$, and an arrow $i : C rightarrow A$. (That is, the object and arrow that define C as a subobject of A.) This object and arrow must satisfy the following conditions:

1. $f circ i = g circ i$
2. $(forall j: D rightarrow A)$ if $f circ j = g circ j$ then $(exists 1 k : D rightarrow C)$ such that $i circ k = j$

That second one is the mouthful. What it says is:

• Suppose that I have any arrow j from some other object D to A:
• if f and g agree on composition about j, then there can only be one unique arrow from C to D which composes with j to get to A.

In other words, (C, i) is a selector for the arrows on which A and B agree; you can only compose an arrow to A in a way that will compose equivalently with f and g to B if you go through (C, i).

Or in diagram form, k in the following diagram is necessarily unique:

There are a couple of interesting properties of equalizers that are worth mentioning. The morphism in an equalizer is a *always* monic arrow (monomorphism); and if it’s epic (an epimorphism), then it must also be iso (an isomorphism).

The pullback is very nearly the same construction as the equalizer we just looked at; except it’s abstracting one step further.

Suppose we have two arrows pointing to the same target: $f : B rightarrow A$ and $g : C rightarrow A$. Then the pullback of of f and g is the triple of an object and two arrows $(B times_A C, p : B times_A C rightarrow B, q : Btimes_A C rightarrow C)$. The elements of this triple must meet the following requirements:

1. $f circ p = g circ q$
2. $(f circ p) : Btimes_A C rightarrow A$
3. for every triple $(D, h : D rightarrow B , k : D rightarrow C)$, there is exactly one unique arrow $langle h,k rangle_A : D rightarrow B times_A C$ where $p circ langle h,k rangle_A = h$, and ${ (x,y) in A times B : f(x) = g(y) }$

Right back where we started, almost. The pullback is an equalizer; working it back shows that.